optimalSensor.label

Return or set the label of an optimal sensor

Syntax



label = obj.label


obj = obj.label(label)

Description



label = obj.label

Returns the label of the current optimalSensor object.



obj = obj.label(label)

Applies a new label to the optimalSensor object

Input Arguments

label

string scalar
A new label for the optimal sensor

Output Arguments

label

string scalar
The current label of the object

obj

scalar optimalSensor object
The object with an updated label.